DRDO- Aeronautical Development Establishment (ADE) Junior Research Fellow, Research Associate Posts | Degree/Master Degree/PH.D. | Apply Now

Sep 29, 2019 | Central Govt. Jobs , DRDO | 0 comments

Aeronautical Development Establishment (ADE), Bengaluru, under the Defence Research Development Organisation, Ministry of Defence, Government of India.

In the latest job notification, DRDO-ADE Bengaluru announces job vacancies for staff posts, in reference to Advertisement No. ADE/HRD/02/2019.

Under DRDO-ADE Junior Research Fellow, RA Recruitment 2019, candidates completed Degree/Master Degree/PH.D. in relevant subjects can apply.

On the basis of Interview, an applicant for the desired post will be finalized on merit.

The selected candidate will be recruited, with salary pay of Rs. 31,000 to Rs. 54,000 per month.

An Interested and qualified candidate has to apply through online mode by 20-10-2019.

Eligibility Criteria For DRDO-ADE Posts:

No. Of Vacancies:  10.

Name of the post:

Research Associate (RA): 1

Junior Research Fellow (JRF): 9

Age Limit:

As on the date of walkin, Candidate maximum age limit should be 35 years.

An applicant from reserved and special categories, the upper age limit is relaxed as per Govt. guidelines.

Education Qualification:

Should complete Degree/Master Degree/PH.D. in relevant Engg subjects from recognized university/institute.

Selection Process:

On the basis Interview.

Steps to apply:

A Candidate has to login https://rac.gov.in/cgibin/2019/advt_ade_jrfra19/.

Select relevant job notification.

Read complete job details.

Fill the application form in the prescribed format through online mode.

And take a print out of application for future use.

Important Dates:

Online application start and end date: 30.09.2019 to 20.10.2019.

Date of walk-in-interview: 05.11.2019 & 06.11.2019.

Venue: ADE, DRDO, Raman Gate, Suranjandas Road, New Thippasandra Post, Bengaluru – 560075..

Job Notification:

https://rac.gov.in/cgibin/2019/advt_ade_jrfra19/public/pdf/advt_ade_jrfra19.pdf?61414441c29db262a922e164c3315c0b=1.

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