CSIR-Indian Institute of Toxicology Research (IITR) Scientist & Senior Scientist Posts | Ph.D/MD/M.E/M.Tech/MVSc | Apply Now
CSIR-Indian Institute of Toxicology Research (formerly, Industrial Toxicology Research Centre), Lucknow, a constituent laboratory of Council of Scientific & Industrial Research, which is an autonomous organization under the Ministry of Science & Technology, Government of India.
In the latest Job Notification, CSIR-IITR announces job vacancies for Scientist & Senior Scientist posts in reference to Advt.No:IITR/1/2020.
Under CSIR-IITR Scientist & Senior Scientist 2020 job notification, candidates who have completed Ph.D/MD/M.E/M.Tech/MVSc in the relevant subjects can apply.
On the basis of the Interview, an applicant for the desired post will be finalized on merit.
The selected candidate will be recruited with salary pay Rs.98,465 to Rs.1,13,228 per month.
An interested and qualified has to apply through online mode by 21-09-2020 till 5.00 pm.
Eligibility Criteria CSIR-IITR Scientist & Senior Scientist Posts:
No.of Vacancies: 11
Name of the Posts:
Senior Scientist- 3
For Scientist: Up to 32 years.
For Senior Scientist: Up to 37 years.
Age relaxation is applicable as per Govt rules.
For General candidates: Rs.100/-
For SC/ST/PwD/Women/Regular CSIR Employees/Abroad candidates: Nil
Candidates who have completed Ph.D/MD/M.E/M.Tech/MVSs in the relevant subjects can apply.
Based on the Interview.
Steps to Apply:
Read the job details at Adv Link
Apply online at IITR
Fill the application form in the prescribed format, attach the necessary documents.
Take the print out of the Application/E-receipt after submission, and send it only through the speed/Registered post to
Director, CSIR-Indian Institute of Toxicology Research, Vishvigyan Bhawan, 31, Mahatma Gandhi Marg, Post Bag No. 80, Lucknow-226001
Starting date of online application submission: 19-08-2020 at 11.00 am.
Last date of online application submission: 21-09-2020 till 5.30 pm.
Last date for hard copy application submission: 05-10-2020 til 5.30 pm.